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\absw8655\absh1200\plain\s0\f0\fs20 \pard\phmrg\pvmrg\posx256\posy1759
\absw8655\absh1200 Von einem Ort A ist für die Verlegung einer 
Gasleitung ein Graben zuerst längs einer geradlinig verlaufenden 
Straße und dann durch schwieriges Gelände zu einem abgelegenen 
Wellness-Hotel zu legen. Die verrechneten Grabungskosten im Gelände 
betragen Euro 75.-, die entlang der Straße Euro 30.- pro Meter.
\par 
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\s0\f0\fs20 \pard\phmrg\pvmrg\posx256\posy5186\absw8594\absh1440 a.)
\tab Wie lang soll entlang der Straße gegraben werden, damit die 
verrechneten Kosten
\tab minimal sind? Berechnen Sie zuerst allgemein, 
dann mit den entsprechenden Zahlen!\par \par \pard\phmrg\pvmrg\posx256
\posy5186\absw8594\absh1440\plain\s0\f0\fs20 \pard\phmrg\pvmrg\posx256
\posy5186\absw8594\absh1440 b.)\tab Um wieviel Prozent ist dieser 
Betrag kleiner gegenüber den Grabungskosten wenn man 
\tab von der 
Straße  im rechten Winkel zum Hotel gräbt?\par \pard\phmrg\pvmrg\posx256
\posy7022\absw8691\absh960\plain\s0\f0\fs20 \pard\phmrg\pvmrg\posx256
\posy7022\absw8691\absh960 Die Erdbewegungsfirma kalkuliert entlang 
der Straße mit folgender Kostenfunktion:
K(x) = 5x + 200. Betrachtet 
man die Anzahl der in Auftrag gegebenen Meter als Stückzahl, so hat 
sich nach langjähriger Beobachtung folgende Funktion für den 
Verkaufspreis pro Meter bewährt:\par \pard\phmrg\pvmrg\posx256\posy8001
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\absh1920\plain\s0\f0\fs20 \pard\phmrg\pvmrg\posx256\posy8736\absw8482
\absh1920 c.)\tab Ermitteln Sie die Erlös- und die Gewinnfunktion! 
Bestimmen Sie die Gewinnschwellen!\par \par d.)\tab Zeichnen Sie die 
Graphen der Verkaufspreis-, der Kosten-, der Erlös- und der
\tab 
Gewinnfunktion!\par \par e.)\tab Bei welchem Verkaufspreis würde die 
Firma einen max. Gewinn erzielen?\par \par f.)\tab Berechnen Sie die 
Fläche zwischen der Erlös- und der Kostenfunktion!\par \pard\phmrg
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\par }

